The name 'i' does not exist in the current context [Answered]RSS

• • Reply
  shijostephen

  Member

  40 Points

  153 Posts

  The name 'i' does not exist in the current context

  Mar 05, 2020 06:55 AM|shijostephen|LINK

  Hi

  I am getting below error in view

  The name 'i' does not exist in the current context

  controller

              double[] latArray = new double[3] { 20.296059, 17.387140, 12.972442 };
              ViewBag.Collection1 = latArray;
  
              double[] longArray = new double[3] { 85.824539, 78.491684, 77.580643 };
              ViewBag.Collection2 = longArray;
  
              model.LocationList = locations;
              return View(model);

  view

          var itemlat=new Array();
          var itemlong=new Array();
          //add markers to map
          @if (Model.LocationList != null)
          {
              foreach (var item in Model.LocationList)
              {
                  @:addMarker(@item.Latitude, @item.Longitude, '@item.Title', '@item.Description', @item.LocationId);
  
  
              }
          }
  
  
          var lineVertices = new Array();
  
          var i = 0;
         for (i = 0; i < 3; i++) {
              var loc= new Microsoft.Maps.Location(@ViewBag.Collection1[i], @ViewBag.Collection2[i]);
              var pin = new Microsoft.Maps.Pushpin(loc);
              lineVertices.push(loc);
          }

  Thanks & Regards

  Shijo

• • Reply
  jiadongm

  Participant

  1170 Points

  439 Posts

  Re: The name 'i' does not exist in the current context

  Mar 05, 2020 08:47 AM|jiadongm|LINK

  Hi shijostephen,

  You should first convet the ViewBage value to json, then you can loop over the Array. Change it like below

         var lineVertices = new Array();
         var arr1 = @Html.Raw(Json.Encode(ViewBag.Collection1));
         var arr2 = @Html.Raw(Json.Encode(ViewBag.Collection2));
         var i;
         for (i = 0; i < 3; i++) 
         {
             var loc= new Microsoft.Maps.Location(arr1[i], arr2[i]);
             var pin = new Microsoft.Maps.Pushpin(loc);
             lineVertices.push(loc);
         }

  Best Regards,

  Jiadong Meng

  MSDN Community Support
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