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Member

43 Points

How to add a page on menu , based on checkbox value ?

Sep 05, 2017 08:09 AM|ddgg|LINK

This is the controller :

<pre> [HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create([Bind(Include = "Id,Template,ShowOnMeny")] Page page)
{
if (ModelState.IsValid)
{
db.Pages.Add(page);
db.SaveChanges();
return RedirectToAction("Index");
}

return View(page);
}</pre>

This is the Create view :

<pre>@model CMSFC.Models.Page

@{
ViewBag.Title = "Create";
Layout = "~/Views/Shared/_Layout.cshtml";
}

<h2>Create</h2>

@using (Html.BeginForm())
{
@Html.AntiForgeryToken()

<div class="form-horizontal">
<h4>Page</h4>
<hr />
@Html.ValidationSummary(true, "", new { @class = "text-danger" })
<div class="form-group">
@Html.LabelFor(model => model.Template, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Template, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Template, "", new { @class = "text-danger" })
</div>
</div>

<div class="form-group">
@Html.LabelFor(model => model.ShowOnMeny, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
<div class="checkbox">
@Html.EditorFor(model => model.ShowOnMeny)
@Html.ValidationMessageFor(model => model.ShowOnMeny, "", new { @class = "text-danger" })
</div>
</div>
</div>

<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}

<div>
@Html.ActionLink("Back to List", "Index")
</div>
</pre>

How can i achieve , if checkbox is checked (true) , to show that page on menu .

This is the Layout(menu) view :

<pre><!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>@ViewBag.Title - My ASP.NET Application</title>
@Styles.Render("~/Content/css")
@Scripts.Render("~/bundles/modernizr")

</head>
<body>
<div class="navbar navbar-inverse navbar-fixed-top">
<div class="container">
<div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse" data-target=".navbar-collapse">
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
@* @Html.ActionLink("Application name", "Index", "Home", new { area = "" }, new { @class = "navbar-brand" })*@
</div>
<div class="navbar-collapse collapse">
<ul class="nav navbar-nav">
<li>@Html.ActionLink("Index", "Index", "Home")</li>
<li>@Html.ActionLink("About", "About", "Home")</li>
<li>@Html.ActionLink("Contact", "Contact", "Home")</li>
<li>@Html.ActionLink("News", "Index", "ContentHtml")</li>
@if (User.Identity.IsAuthenticated)
{
if (User.IsInRole("Admin") || User.IsInRole("Guest"))
{
<li>@Html.ActionLink("PageConfig", "Index", "PageConfigs")</li>
<li>@Html.ActionLink("Pages", "Index", "Pages")</li>
}
}

</ul>

@Html.Partial("_LoginPartial")
</div>
</div>
</div>
<div class="container body-content">
@RenderBody()
<hr />
<footer>
<p></p>
</footer>
</div>

@Scripts.Render("~/bundles/jquery")
@Scripts.Render("~/bundles/bootstrap")
@RenderSection("scripts", required: false)
</body>
</html>
</pre>

Reply

AngelinaJoli...

Contributor

5290 Points

2307 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 06, 2017 07:18 AM|AngelinaJolie|LINK

Hi ddgg,

Please refer to this way to add a page based on checkbbox value;

In your main view page:

@if(Model .CheckboxColumnName ==true){ 
@Html.Partial("_youPartialViewPage")
}

please let me know if any problem;

With regards,

Angelina Jolie

MSDN Community Support
Please remember to click "Mark as Answer" the responses that resolved your issue.
If you have any compliments or complaints to MSDN Support, feel free to contact MSDNFSF@microsoft.com.

Reply

ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 06, 2017 07:31 AM|ddgg|LINK

Hmm sir/miss , im not understanding this close exactly ..

So when i hit create page and check TRUE the checkbox , example Page "Test",that page should be on the menu . In the Layout view i sent above , here in this section :

<div class="navbar-collapse collapse">
<ul class="nav navbar-nav">
<li>@Html.ActionLink("Index", "Index", "Home")</li>
<li>@Html.ActionLink("About", "About", "Home")</li>
<li>@Html.ActionLink("Contact", "Contact", "Home")</li>
<li>@Html.ActionLink("News", "Index", "ContentHtml")</li>
@if (User.Identity.IsAuthenticated)
{
if (User.IsInRole("Admin") || User.IsInRole("Guest"))
{
<li>@Html.ActionLink("PageConfig", "Index", "PageConfigs")</li>
<li>@Html.ActionLink("Pages", "Index", "Pages")</li>
}
}

</ul>

@Html.Partial("_LoginPartial")
</div>

Then , that recently-created page "Test" should show on Menu like this :
<li>@Html.ActionLink("PageConfig", "Index", "PageConfigs")</li>
<li>@Html.ActionLink("Pages", "Index", "Pages")</li>
====HERE COMES TEST PAGE TAB =======
====HERE COMES TEST1 PAGE TAB=======

AND SO ON.....

So this is the Layout view of entire application:

<pre><!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>@ViewBag.Title - My ASP.NET Application</title>
@Styles.Render("~/Content/css")
@Scripts.Render("~/bundles/modernizr")

</head>
<body>
<div class="navbar navbar-inverse navbar-fixed-top">
<div class="container">
<div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse" data-target=".navbar-collapse">
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
@* @Html.ActionLink("Application name", "Index", "Home", new { area = "" }, new { @class = "navbar-brand" })*@
</div>
<div class="navbar-collapse collapse">
<ul class="nav navbar-nav">
<li>@Html.ActionLink("Index", "Index", "Home")</li>
<li>@Html.ActionLink("About", "About", "Home")</li>
<li>@Html.ActionLink("Contact", "Contact", "Home")</li>
<li>@Html.ActionLink("News", "Index", "ContentHtml")</li>
@if (User.Identity.IsAuthenticated)
{
if (User.IsInRole("Admin") || User.IsInRole("Guest"))
{
<li>@Html.ActionLink("PageConfig", "Index", "PageConfigs")</li>
<li>@Html.ActionLink("Pages", "Index", "Pages")</li>
}
}

</ul>

@Html.Partial("_LoginPartial")
</div>
</div>
</div>
<div class="container body-content">
@RenderBody()
<hr />
<footer>
<p></p>
</footer>
</div>

@Scripts.Render("~/bundles/jquery")
@Scripts.Render("~/bundles/bootstrap")
@RenderSection("scripts", required: false)
</body>
</html>
</pre>

So how to fit these two ?!

This is create view:

<pre>@model CMSFC.Models.Page

@{
ViewBag.Title = "Create";
Layout = "~/Views/Shared/_Layout.cshtml";
}

<h2>Create</h2>

@using (Html.BeginForm())
{
@Html.AntiForgeryToken()

<div class="form-horizontal">
<h4>Page</h4>
<hr />
@Html.ValidationSummary(true, "", new { @class = "text-danger" })
<div class="form-group">
@Html.LabelFor(model => model.Template, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Template, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Template, "", new { @class = "text-danger" })
</div>
</div>

<div class="form-group">
@Html.LabelFor(model => model.ShowOnMeny, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
<div class="checkbox">
@Html.EditorFor(model => model.ShowOnMeny)
@Html.ValidationMessageFor(model => model.ShowOnMeny, "", new { @class = "text-danger" })
</div>
</div>
</div>

<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}

<div>
@Html.ActionLink("Back to List", "Index")
</div>
</pre>

Reply

AngelinaJoli...

Contributor

5290 Points

2307 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 02:53 AM|AngelinaJolie|LINK

Hi ddgg,

Very sorry for my later , it 's my mistake:) .

Based on your code , we could just keep your Layout page and put something code into Create Page:

at Layout.cshtml:

<pre><!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>@ViewBag.Title - My ASP.NET Application</title>
@Styles.Render("~/Content/css")
@Scripts.Render("~/bundles/modernizr")

</head>
<body>
<div class="navbar navbar-inverse navbar-fixed-top">
<div class="container">
<div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse" data-target=".navbar-collapse">
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
@* @Html.ActionLink("Application name", "Index", "Home", new { area = "" }, new { @class = "navbar-brand" })*@ 
</div>
<div class="navbar-collapse collapse">
<ul class="nav navbar-nav">
<li>@Html.ActionLink("Index", "Index", "Home")</li>
<li>@Html.ActionLink("About", "About", "Home")</li>
<li>@Html.ActionLink("Contact", "Contact", "Home")</li>
<li>@Html.ActionLink("News", "Index", "ContentHtml")</li>
@if (User.Identity.IsAuthenticated)
{
if (User.IsInRole("Admin") || User.IsInRole("Guest"))
{
<li>@Html.ActionLink("PageConfig", "Index", "PageConfigs")</li>
<li>@Html.ActionLink("Pages", "Index", "Pages")</li>
}
}

</ul>

@Html.Partial("_LoginPartial")
</div>
</div>
</div>
<div class="container body-content">
@RenderBody()
<hr />
<footer>
<p></p>
</footer>
</div>

@Scripts.Render("~/bundles/jquery")
@Scripts.Render("~/bundles/bootstrap")
@RenderSection("scripts", required: false)
</body>
</html>
</pre>

at create page:

<pre>@model CMSFC.Models.Page

@{
ViewBag.Title = "Create";
Layout = "~/Views/Shared/_Layout.cshtml";
}

<h2>Create</h2>

@using (Html.BeginForm()) 
{
@Html.AntiForgeryToken()

<div class="form-horizontal">
<h4>Page</h4>
<hr />
@Html.ValidationSummary(true, "", new { @class = "text-danger" })
<div class="form-group">
@Html.LabelFor(model => model.Template, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Template, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Template, "", new { @class = "text-danger" })
</div>
</div>

<div class="form-group">
@Html.LabelFor(model => model.ShowOnMeny, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
<div class="checkbox">
@Html.EditorFor(model => model.ShowOnMeny)
@Html.ValidationMessageFor(model => model.ShowOnMeny, "", new { @class = "text-danger" })
</div>
</div>
</div>
@if(Model .CheckboxColumnName ==true){  // please note this line code 
@Html.Partial("_youPartialViewPage")
}
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}

<div>
@Html.ActionLink("Back to List", "Index")
</div>
</pre>

Best regards,

Angelina Jolie

MSDN Community Support
Please remember to click "Mark as Answer" the responses that resolved your issue.
If you have any compliments or complaints to MSDN Support, feel free to contact MSDNFSF@microsoft.com.

Reply

ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 10:56 AM|ddgg|LINK

here is what i did :

public ActionResult Menu()
      {
          return PartialView("Menu", db.Pages.ToList().Where(m => m.ShowOnMeny == true).ToList());
 
 
 
 
      }

 
@model IEnumerable<CMSFC.Models.Page>
 
@{
 
//    Layout = "~/Views/Shared/_Layout2.cshtml";
}
 
 
 
@foreach (var item in Model.Where(m=> m.ShowOnMeny==true))
{
 
 
 
 
    <li>@Html.ActionLink("P", "Details", new { id = item.Id })</li>
 
 
 
 
 
}

and in layout:

<li>@Html.Partial("Menu")</li>

But im getting this error :

Server Error in '/' Application.

The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.InvalidOperationException: The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Source Error:

Line 38:                             <li>@Html.ActionLink("PageConfig", "Index", "PageConfigs")</li>
Line 39:                                 <li>@Html.ActionLink("Pages", "Index", "Pages")</li>
Line 40:                             <li>@Html.Partial("Menu")</li>
Line 41: 
Line 42:

Source File: S:\My Documents\Visual Studio 2015\Projects\CMSFC\CMSFC\Views\Shared\_Layout.cshtml Line: 40

Stack Trace:

Reply

AngelinaJoli...

Contributor

5290 Points

2307 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 11:14 AM|AngelinaJolie|LINK

please change @Html.Partial("Menu")</li> to @Html.Action("Menu")</li>,best records,Jolie.

MSDN Community Support
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Reply

ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 11:23 AM|ddgg|LINK

Now the pages appear on menu , but everything else is not working. For example , if i click one on these pages on the menu like this :
http://localhost:53781/Pages/Details/1

Server Error in '/' Application.

The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.InvalidOperationException: The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Source Error:

An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below.

Stack Trace:

Another error :

http://localhost:53781/

Server Error in '/' Application.

The model item passed into the dictionary is of type 'System.Data.Entity.Infrastructure.DbQuery`1[CMSFC.Models.ContentHtml]', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.InvalidOperationException: The model item passed into the dictionary is of type 'System.Data.Entity.Infrastructure.DbQuery`1[CMSFC.Models.ContentHtml]', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Source Error:

Line 129:             {
Line 130:                 // Html.RenderAction("Tabelar", "ContentHtml", module.Control);
Line 131:                 Html.RenderAction(module.Control, "ContentHtml", new { id = module.Content });
Line 132:             }
Line 133:

Source File: S:\My Documents\Visual Studio 2015\Projects\CMSFC\CMSFC\Views\Home\Index.cshtml Line: 131

Reply

mgebhard

All-Star

43391 Points

18530 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 11:31 AM|mgebhard|LINK

Perhaps explain what you are trying to do at a high level. Are you trying to create a table driven menu?

Reply

ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 11:33 AM|ddgg|LINK

No , i have a layout view that contains the app menu like this:

<div class="navbar-collapse collapse">
               <ul class="nav navbar-nav">
                   <li>@Html.ActionLink("Index", "Index", "Home")</li>
                   <li>@Html.ActionLink("About", "About", "Home")</li>
                   <li>@Html.ActionLink("Contact", "Contact", "Home")</li>
                   <li>@Html.ActionLink("News", "Index", "ContentHtml")</li>
                   @if (User.Identity.IsAuthenticated)
                   {
                       if (User.IsInRole("Admin") || User.IsInRole("Guest"))
                       {
 
                           <li>@Html.ActionLink("PageConfig", "Index", "PageConfigs")</li>
                               <li>@Html.ActionLink("Pages", "Index", "Pages")</li>
                            
                           <li>@Html.Action("Menu"))</li>

 this view <li>@Html.Action("Menu"))</li>  than adds pages ,that have the option ShowOnMeny == true , on the menu.

Reply

AngelinaJoli...

Contributor

5290 Points

2307 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 11:48 AM|AngelinaJolie|LINK

what's Tabelar method?and please check error massage in details.it needs page list.

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ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 11:49 AM|ddgg|LINK

public ActionResult Tabelar(string id)
   {
       //  return View(db.ContentHtmls.Take(6).ToList());
       var movies = db.ContentHtmls.Where(s => s.Content.Contains(id));
       //  select m;
 
       //   if (!String.IsNullOrEmpty(id))
       //    {
       //    movies = movies.Where(s => s.Content.Contains(id));
       // }
 
       return View(movies);
   }

@model IEnumerable<CMSFC.Models.ContentHtml>
 
 
<style type="text/css">
 
 
    a.classname
{
    background: url(/Images/details_open.png) no-repeat top left;
     display: block;
     width: 100px;
     height: 100px;
}
 
</style>
 
 
 
<link href="~/Content/PagedList.css" rel="stylesheet" type="text/css" />
<h1></h1>
 
@if (User.Identity.IsAuthenticated)
{
    if (User.IsInRole("Admin"))
    {
        <p>
            @Html.ActionLink("  ", "Create", null, new { @class = "classname" })
 
 
        </p>
    }
}
 
 
 
<div style="display: inline-block">
    @for (int i = 0; i < Model.Count(); i += 3)
    {
        <div class="row"  style="height=40px;">
            @{
                var tblTestList = Model.ToList();
                for (int j = 0; j <= 2 && i + j < Model.Count(); j++)
                {
                    <div class="col-md-4">
                        <br />
                        <div style='vertical-align:middle; display:inline;'>
                            <img alt="" src="@tblTestList[i + j].Ctl" width="100" height="60" style='vertical-align:middle;'/>
 
                            <div><b>@tblTestList[i + j].Title1</b></div>
                        </div>
                        <br />
                        <div> @tblTestList[i + j].PublishDate</div>
                        <br />
 
                        <div>@Html.Raw(HttpUtility.HtmlDecode(tblTestList[i + j].ShortDescription1))</div>
 
 
                        <div>@Html.ActionLink("Read more ", "Details", new { id = tblTestList[i + j].Id })</div>
                        <br />
                        <br />
                    </div>
                }
            }
        </div>
                }
</div>
 
 
<h2></h2>

Reply

AngelinaJoli...

Contributor

5290 Points

2307 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 11:55 AM|AngelinaJolie|LINK

it should be, Html.Action("Tabelar", new { id = module.Content }); please use static value at first time.

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Reply

ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 12:01 PM|ddgg|LINK

Okay , that is done .What about the first error when im clicking to one of added pages in menu:

http://localhost:53781/Pages/Details/1

Server Error in '/' Application.

The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.InvalidOperationException: The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Source Error:

An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below.

Stack Trace:

Reply

AngelinaJoli...

Contributor

5290 Points

2307 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 12:10 PM|AngelinaJolie|LINK

which line alerts error?

MSDN Community Support
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Reply

ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 12:13 PM|ddgg|LINK

just this url works fine :

http://localhost:53781/Pages/

when i click on the pages in menu like this :

http://localhost:53781/Pages/Details/1

it alerts this error :

Server Error in '/' Application.

The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.InvalidOperationException: The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Source Error:

An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below.

Stack Trace:

[InvalidOperationException: The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.]
   System.Web.Mvc.ViewDataDictionary`1.SetModel(Object value) +175
   System.Web.Mvc.ViewDataDictionary..ctor(ViewDataDictionary dictionary) +107
   System.Web.Mvc.WebViewPage`1.SetViewData(ViewDataDictionary viewData) +49
   System.Web.Mvc.WebViewPage.ConfigurePage(WebPageBase parentPage) +57
   System.Web.WebPages.<>c__DisplayClass3.<RenderPageCore>b__2(TextWriter writer) +218
   System.Web.WebPages.HelperResult.WriteTo(TextWriter writer) +10
   System.Web.WebPages.WebPageBase.Write(HelperResult result) +80
   System.Web.WebPages.WebPageBase.RenderSurrounding(String partialViewName, Action`1 body) +63
   System.Web.WebPages.WebPageBase.PopContext() +237
   System.Web.WebPages.WebPageBase.ExecutePageHierarchy(WebPageContext pageContext, TextWriter writer, WebPageRenderingBase startPage) +98
   System.Web.Mvc.RazorView.RenderView(ViewContext viewContext, TextWriter writer, Object instance) +256
   System.Web.Mvc.BuildManagerCompiledView.Render(ViewContext viewContext, TextWriter writer) +107
   System.Web.Mvc.ViewResultBase.ExecuteResult(ControllerContext context) +291
   System.Web.Mvc.ControllerActionInvoker.InvokeActionResult(ControllerContext controllerContext, ActionResult actionResult) +13
   System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilterRecursive(IList`1 filters, Int32 filterIndex, ResultExecutingContext preContext, ControllerContext controllerContext, ActionResult actionResult) +56
   System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilterRecursive(IList`1 filters, Int32 filterIndex, ResultExecutingContext preContext, ControllerContext controllerContext, ActionResult actionResult) +420
   System.Web.Mvc.ControllerActionInvoker.InvokeActionResultWithFilters(ControllerContext controllerContext, IList`1 filters, ActionResult actionResult) +52
   System.Web.Mvc.Async.<>c__DisplayClass2b.<BeginInvokeAction>b__1c() +173
   System.Web.Mvc.Async.<>c__DisplayClass21.<BeginInvokeAction>b__1e(IAsyncResult asyncResult) +100
   System.Web.Mvc.Async.WrappedAsyncResult`1.CallEndDelegate(IAsyncResult asyncResult) +10
   System.Web.Mvc.Async.WrappedAsyncResultBase`1.End() +49
   System.Web.Mvc.Async.AsyncControllerActionInvoker.EndInvokeAction(IAsyncResult asyncResult) +27
   System.Web.Mvc.Controller.<BeginExecuteCore>b__1d(IAsyncResult asyncResult, ExecuteCoreState innerState) +13
   System.Web.Mvc.Async.WrappedAsyncVoid`1.CallEndDelegate(IAsyncResult asyncResult) +29
   System.Web.Mvc.Async.WrappedAsyncResultBase`1.End() +49
   System.Web.Mvc.Controller.EndExecuteCore(IAsyncResult asyncResult) +36
   System.Web.Mvc.Controller.<BeginExecute>b__15(IAsyncResult asyncResult, Controller controller) +12
   System.Web.Mvc.Async.WrappedAsyncVoid`1.CallEndDelegate(IAsyncResult asyncResult) +22
   System.Web.Mvc.Async.WrappedAsyncResultBase`1.End() +49
   System.Web.Mvc.Controller.EndExecute(IAsyncResult asyncResult) +26
   System.Web.Mvc.Controller.System.Web.Mvc.Async.IAsyncController.EndExecute(IAsyncResult asyncResult) +10
   System.Web.Mvc.MvcHandler.<BeginProcessRequest>b__5(IAsyncResult asyncResult, ProcessRequestState innerState) +21
   System.Web.Mvc.Async.WrappedAsyncVoid`1.CallEndDelegate(IAsyncResult asyncResult) +29
   System.Web.Mvc.Async.WrappedAsyncResultBase`1.End() +49
   System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult) +28
   System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result) +9
   System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +9644037
   System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +155

Version Information: Microsoft .NET Framework Version:4.0.30319; ASP.NET Version:4.6.1

Reply

AngelinaJoli...

Contributor

5290 Points

2307 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 12:14 PM|AngelinaJolie|LINK

so you need show us details view page.and details action method.

MSDN Community Support
Please remember to click "Mark as Answer" the responses that resolved your issue.
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Reply

ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 12:15 PM|ddgg|LINK

@model CMSFC.Models.Page
 
@{
    ViewBag.Title = "Details";
    Layout = "~/Views/Shared/_Layout.cshtml";
}
 
<h2>Details</h2>
 
<div>
    <h4>Page</h4>
    <hr />
    <dl class="dl-horizontal">
        <dt>
            @Html.DisplayNameFor(model => model.Template)
        </dt>
 
        <dd>
           
            @Html.Raw(Model.Template)
        </dd>
 
        <dt>
            @Html.DisplayNameFor(model => model.ShowOnMeny)
        </dt>
 
        <dd>
            @Html.DisplayFor(model => model.ShowOnMeny)
        </dd>
 
    </dl>
</div>
<p>
    @Html.ActionLink("Edit", "Edit", new { id = Model.Id }) |
    @Html.ActionLink("Back to List", "Index")
</p>

// GET: Pages/Details/5
        public ActionResult Details(int? id)
        {
            if (id == null)
            {
                return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
            }
            Page page = db.Pages.Find(id);
            if (page == null)
            {
                return HttpNotFound();
            }
            return View(page);
        }

Reply

AngelinaJoli...

Contributor

5290 Points

2307 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 15, 2017 12:18 PM|AngelinaJolie|LINK

Hi ddgg,

I did an complete project and it has no any error with CURD page based on your code ;

Here is the full code:

in layout.cshtml:

<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
    <meta charset="utf-8" />
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>@ViewBag.Title -   ASP.NET  </title>
    @Styles.Render("~/Content/css")
    @Scripts.Render("~/bundles/modernizr")

</head>
<body>
    <div class="navbar navbar-inverse navbar-fixed-top">
        <div class="container">
            <div class="navbar-header">
                <button type="button" class="navbar-toggle" data-toggle="collapse" data-target=".navbar-collapse">
                    <span class="icon-bar"></span>
                    <span class="icon-bar"></span>
                    <span class="icon-bar"></span>
                </button>
                @Html.Action("Menu","Profiles")
                @Html.ActionLink("my project", "Index", "Home", new { area = "" }, new { @class = "navbar-brand" })
            </div>
            <div class="navbar-collapse collapse">
                <ul class="nav navbar-nav">
             ....
                </ul>
                @Html.Partial("_LoginPartial")
            </div>
        </div>
    </div>
    <div class="container body-content">
        @RenderBody()
        <hr />
        <footer>
            <p>&copy; @DateTime.Now.Year -  </p>
        </footer>
    </div>

    @Scripts.Render("~/bundles/jquery")
    @Scripts.Render("~/bundles/bootstrap")
    @RenderSection("scripts", required: false)
</body>
</html>

then ,in ProfilesController .cshtml:

 public class ProfilesController : Controller
    {
        private ApplicationDbContext db = new ApplicationDbContext();
        public ActionResult Menu()
        {
            return PartialView("Menu", db.Profiles.ToList() );
        }

        // GET: Profiles
        public ActionResult Index()
        {
           
            return View(db.Profiles.ToList());
        }
        

        // GET: Profiles/Details/5
        public ActionResult Details(int? id)
        {
            if (id == null)
            {
                return new HttpStatusCodeResult(HttpStatusCode.BadRequest);
            }
            Profile profile = db.Profiles.Find(id);

and in index.cshtml:

@model IEnumerable<MVCGuo.Models.Profile>

@{
    ViewBag.Title = "Index";
}

in detail.shtml:

@model MVCGuo.Models.Profile

@{
    ViewBag.Title = "Details";
}

in Menu.cshtml:

@model IEnumerable<   MVCGuo.Models.Profile >
@{
    ViewBag.Title = "Menu";
 }

@foreach (var item in Model )
{
    <li>@Html.ActionLink("P", "Details", new { id = item.ProfileId })</li>
}
<h2>Menu</h2>

Best regards,

Angelina Jolie

MSDN Community Support
Please remember to click "Mark as Answer" the responses that resolved your issue.
If you have any compliments or complaints to MSDN Support, feel free to contact MSDNFSF@microsoft.com.

Reply

ddgg

Member

43 Points

106 Posts

Re: How to add a page on menu , based on checkbox value ?

Sep 18, 2017 10:44 AM|ddgg|LINK

I did something different :

Layout:

<div class="navbar-collapse collapse">
            <ul class="nav navbar-nav">
                <li>@Html.ActionLink("Index", "Index", "Home")</li>
                <li>@Html.ActionLink("About", "About", "Home")</li>
                <li>@Html.ActionLink("Contact", "Contact", "Home")</li>
                <li>@Html.ActionLink("News", "Index", "ContentHtml")</li>
                @if (User.Identity.IsAuthenticated)
                {
                    if (User.IsInRole("Admin") || User.IsInRole("Guest"))
                    {


                           <li>@Html.Action("Menu"))</li>

The partial view :

@model IEnumerable< abc.Models.Test>

   @foreach(var item in Model.Where(m => m.Show== true))
    {
       <li> 
          @Html.ActionLink("P", "Details", new { id = item.Id }) 
       </li>
    }

action:

public ActionResult Menu()
{
  return PartialView("Menu", db.Test.ToList().Where(m => m.Show == true).ToList());
}

I dont know whyy , but today this is workingg !!! maybe that is monday haha . Anyway thanks for all your contribute , it really helped me.

<div class="vote" style="margin: 0px; padding: 0px; border: 0px; font-style: inherit; font-variant: inherit; font-weight: inherit; font-stretch: inherit; font-size: inherit; line-height: inherit; font-family: inherit; vertical-align: baseline; text-align: center; min-width: 46px;">0down vote favorite <div class="favoritecount" style="margin: 0px; padding: 0px; border: 0px; font-style: inherit; font-variant: inherit; font-weight: inherit; font-stretch: inherit; font-size: inherit; line-height: inherit; font-family: inherit; vertical-align: baseline;"></div> </div>

This is Layout view :

<div class="navbar-collapse collapse">
            <ul class="nav navbar-nav">
                <li>@Html.ActionLink("Index", "Index", "Home")</li>
                <li>@Html.ActionLink("About", "About", "Home")</li>
                <li>@Html.ActionLink("Contact", "Contact", "Home")</li>
                <li>@Html.ActionLink("News", "Index", "ContentHtml")</li>
                @if (User.Identity.IsAuthenticated)
                {
                    if (User.IsInRole("Admin") || User.IsInRole("Guest"))
                    {


                           <li>@Html.Action("Menu"))</li>

</div> </div>

How to add a page on menu , based on checkbox value ? [Answered]RSS

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How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Server Error in '/' Application.

The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Server Error in '/' Application.

The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Server Error in '/' Application.

The model item passed into the dictionary is of type 'System.Data.Entity.Infrastructure.DbQuery`1[CMSFC.Models.ContentHtml]', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Server Error in '/' Application.

The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Server Error in '/' Application.

The model item passed into the dictionary is of type 'CMSFC.Models.Page', but this dictionary requires a model item of type 'System.Collections.Generic.IEnumerable`1[CMSFC.Models.Page]'.

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?

Re: How to add a page on menu , based on checkbox value ?