Dictionary - How to return Dictionary value as a method or function.[Answered] RSS

• • Reply
  gani7787

  Member

  209 Points

  701 Posts

  Dictionary - How to return Dictionary value as a method or function.

  Jul 18, 2017 12:22 PM|gani7787|LINK

  Hi,

  How to return TempSub value as method or function.

  See my full code.

  double strReturnvalue = GetMarks(A,B,C,D,E,F,str); // Main and returns Tempsub value

  public static double GetMarks(double A,double B,double C,double D,double E,double F,String str)
  
  double retCondition = 0.0;
  str = "Sub1 = A+B-C+D-A,Sub2=D+E,Sub3=F+G";
  string[] words1 = str.Split('#');
  Dictionary<string, double> TempSub = new Dictionary<string, double>();
  for (int i = 0; i < words1.Length; i++)
  {
  double n = 0.0;
  string[] words2 = words1[i].Split('='); // Again splitting the values for Sub1 = A+B // Second split

  string[] words3 = words2[1].Split('+');
  for (int j = 0; j < words3.Length; j++)
  {
  double m = 0.0;
  double sub = 0.0;
  string[] words4 = words3[j].Split('-');
  for (int k = 0; k < words4.Length; k++)
  {
  switch (words4[k].Trim())
  {
  case "A":
  sub = 10;
  break;
  case "B":
  sub = 20;
  break;
  case "C":
  sub = 30;
  break;
  case "D":
  sub = 180;
  break;
  default:
  sub = 0;
  break;
  }
  if (k == 0)
  {
  m += sub;
  }
  else
  {
  m -= sub;
  }
  }
  n += m;
  }
  TempSub.Add(words2[0], n); // So Sub1 will be the variables
  }

  retCondition = TempSub ??????? // Error
  return retCondition;

  
  }

  How to return TempSub value to method or function..?

• • Reply
  JBetancourt

  Participant

  1380 Points

  608 Posts

  Re: Dictionary - How to return Dictionary value as a method or function.

  Jul 18, 2017 01:31 PM|JBetancourt|LINK

  change the return type of your method to Dictionary<string,double>:

  public static Dictionary<string, double> GetMarks(double A,double B,double C,double D,double E,double F,String str)

  then change the strReturnValue and retCondition variable declarations to a dictionary as well:

  var strReturnvalue = GetMarks(A,B,C,D,E,F,str); // Main and returns Tempsub value

  and

  Dictionary<string, double> retCondition;

  The whole thing:

  var strReturnvalue = GetMarks(A, B, C, D, E, F, str); // Main and returns Tempsub value
  
  public static Dictionary < string, double > GetMarks(double A, double B, double C, double D, double E, double F, String str) {
  	Dictionary < string, double > retCondition;
  	str = "Sub1 = A+B-C+D-A,Sub2=D+E,Sub3=F+G";
  	string[] words1 = str.Split('#');
  	Dictionary < string, double > TempSub = new Dictionary < string, double > ();
  	for (int i = 0; i < words1.Length; i++) {
  	double n = 0.0;
  	string[] words2 = words1[i].Split('='); // Again splitting the values for Sub1 = A+B // Second split
  	
  	string[] words3 = words2[1].Split('+');
  	for (int j = 0; j < words3.Length; j++) {
  	double m = 0.0;
  	double sub = 0.0;
  	string[] words4 = words3[j].Split('-');
  	for (int k = 0; k < words4.Length; k++) {
  		switch (words4[k].Trim()) {
  		case "A":
  		sub = 10;
  		break;
  		case "B":
  		sub = 20;
  		break;
  		case "C":
  		sub = 30;
  		break;
  		case "D":
  		sub = 180;
  		break;
  		default:
  		sub = 0;
  		break;
  		}
  		if (k == 0) {
  		m += sub;
  		} else {
  		m -= sub;
  		}
  	}
  	n += m;
  	}
  	TempSub.Add(words2[0], n); // So Sub1 will be the variables
  	}
  	
  	retCondition = TempSub // Error
  	return retCondition;
  }

  -----------------
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• • Reply
  Billy Liu

  Contributor

  2260 Points

  815 Posts

  Re: Dictionary - How to return Dictionary value as a method or function.

  Jul 19, 2017 05:32 AM|Billy Liu|LINK

  Hi gani7787,

  You could refer to my answer in your previous post:

  https://forums.asp.net/p/2125211/6153447.aspx

  Best Regards,

  Billy

  MSDN Community Support
  Please remember to click "Mark as Answer" the responses that resolved your issue.
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