How to simulate WCF service channel into faulted state RSS

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  nrk_hi

  Member

  110 Points

  254 Posts

  How to simulate WCF service channel into faulted state

  Jan 31, 2017 03:32 PM|nrk_hi|LINK

  Hi ,

  I created a simple wcf service which looks as below, in the service Divide() method trying to create faulted excpetion , when I try to consume Divide() method it goes to catch block which uses faulted exception, but service channel state is opened even after it throws faulted exception, how to simulate faulted state for service instance for testing

  Interface:-

         [ServiceContract]
  	public interface IService1
  	{
  		[OperationContract]
  		int Divide(int n1, int n2);
  	}
  

  Service implementation:-

  public class Service1 : IService1
  	{
  		public int Divide(int n1, int n2)
  		{
  			try
  			{
  				return n1 / n2;
  			}
  			catch (DivideByZeroException e)
  			{
  
  				throw new FaultException(e.Message);
  			}
  		}
  	}

  Consuming service in console application:-

  static void Main(string[] args)
  		{
  			ServiceReference1.Service1Client svc = new ServiceReference1.Service1Client();
  			try
  			{
  				svc.Divide(7, 0);
  
  			}
  			catch (FaultException ex)
  			{
  				string status = svc.State.ToString(); // here state still shows as "opened" ,expected to be faulted
  			}
  			catch (Exception ex)
  			{
  				string status = svc.State.ToString();
  
  			}
  			//int a = svc.getvalue(2);
  		}
  	}

  Ravikumar
• • Reply
  Chris Zhao

  All-Star

  17652 Points

  3510 Posts

  Re: How to simulate WCF service channel into faulted state

  Feb 02, 2017 07:26 AM|Chris Zhao|LINK

  Hi Nrk_hi,

  The communication state is going to faulted sate due to protocol error, unhandled exception or timeout.

  reference:

  http://stackoverflow.com/a/3574053

  https://msdn.microsoft.com/en-us/library/ff183865.aspx

  Best Regards,

  Chris