xslt: how can I fine-tune the href attribute of an anchor tag?[Answered] RSS

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  HatesSunligh...

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  xslt: how can I fine-tune the href attribute of an anchor tag?

  May 03, 2015 11:58 PM|HatesSunlight|LINK

  I have a successful XSLT file (shown below), but what I'd like to do is adjust 

  <a href="{@url}">

  so that when when the transformed xml file appears in my asp:xml control on my aspx page, it appears as:

  <a href="<%# Page.ResolveClientURL(""{@url}"") %>">

  I figured this wouldn't work, but this is the result I need. Is there some way to do this right?

  Here is the full xslt script, with the relevant line bolded:

  Thanks for any ideas.

  <?xml version="1.0" encoding="utf-8"?>
  <xsl:stylesheet version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:map="http://schemas.microsoft.com/AspNet/SiteMap-File-1.0"
  exclude-result-prefixes="map">
  
      <xsl:output method="xml"  version="1.0" encoding="utf-8" indent="yes" omit-xml-declaration="yes" />
      <xsl:strip-space elements="*"/>   
      
      <xsl:template  match="map:siteMapNode">
          <li>
              <a href="{@url}">
                  <xsl:value-of select="@title"/>
              </a>
              <xsl:if test="map:siteMapNode">
                  <xsl:call-template name="mapNode"/>
              </xsl:if>
          </li>
      </xsl:template>
  
      <xsl:template name="mapNode" match="map:siteMap">
          <xsl:choose>
              <xsl:when test="@*">
                  <ul>
                      <xsl:apply-templates />
                  </ul>
              </xsl:when>
              <xsl:otherwise>                
                  <ul id="">
                      <xsl:apply-templates />
                  </ul>                
              </xsl:otherwise>                
          </xsl:choose>
          
      </xsl:template>
  
  </xsl:stylesheet>

  xslt href url

• • Reply
  HatesSunligh...

  Member

  16 Points

  155 Posts

  Re: xslt: how can I fine-tune the href attribute of an anchor tag?

  May 04, 2015 01:10 PM|HatesSunlight|LINK

  The key isn't to do this in the XSLT document, but rather the ASP.NET page.

  <script runat="server">
      Public MenuList As String = String.Empty
      Protected Sub Page_Load(sender As Object, e As EventArgs)
          Dim ds As New DataSet()
          ds.ReadXml(Server.MapPath("~/Web.sitemap"))
          
          ' this for-each block resolves client URL
          
          For Each dr As DataRow In ds.Tables(0).Rows
              Dim tempURL As String = Page.ResolveClientUrl(dr("url").ToString)
              dr("url") = tempURL
          Next
          
          Dim strXML As String = ds.GetXml()
          MenuList = GetHtml(Server.MapPath("~/sitemap_static_3.xslt"), strXML)
      End Sub
  
      Public Shared Function GetHtml(xsltPath As String, xml As String) As String
          Dim stream As New MemoryStream(ASCIIEncoding.[Default].GetBytes(xml))
          Dim document As New XPathDocument(stream)
          Dim writer As New StringWriter()
          Dim transform As New XslCompiledTransform()
          transform.Load(xsltPath)
          transform.Transform(document, Nothing, writer)
          Return writer.ToString()
      End Function
  </script>

  
  In the body: 

  <div id="content">
          <ul>
              <li>
                  <a href='<%= Page.ResolveUrl("~/index.aspx")%>'>Homepage</a>
              </li>
              <%= MenuList%>
          </ul>
      </div>

  xslt href url