Issue with replacing xml nodes[Answered] RSS

• • Reply
  Chithra_Iyer

  Member

  46 Points

  459 Posts

  Issue with replacing xml nodes

  Jul 09, 2014 01:36 PM|Chithra_Iyer|LINK

  I want to replace the entire token node from the below xml 

  <s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
    <s:Header>
      <s:Context xmlns="urn:jspin:xu:services:schema:message:common:jspindata:v01">
        <RequestId>uuid:b638ad89-c6db-4774-b8f0-40d3cd36ccd6</RequestId>
      </s:Context>
      <s:MetaData xmlns:h="urn:jspin:xu:services:schema:message:common:jspindata:v01">
        <ID xmlns="urn:jspin:xu:services:schema:message:common:jspinmsdata:v01">InsPortal</ID>
      </s:MetaData>
      <h:Token s:mustUnderstand="1" h="urn:jspin:xu:services:schema:message:common:jspindata:v01">
          <SysToken wsu:Id="44e314f6-f4aa-4773-94ee-b527aeecfc3e"/>
          <User>test</User>
          <Created>2014-07-09T17:13:14Z</Created>
       </h:Token>
    </s:Header>
  </s:Envelope>

  
  I tried using XMldocument and Xdoc for this but not getting the entire node.Also i want to replace the  entire Token node with a different Token node from another XML.

  Please could you help me out here

  Chithra_Iyer
• • Reply
  Abidali440

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  4 Posts

  Re: Issue with replacing xml nodes

  Jul 10, 2014 02:39 AM|Abidali440|LINK

  You can use RegularExpression to find and replace entire node from the xml. Below is the example you can use to do same.

  public String FindAndReplaceXmlNode(String xml, String element, String defaultValue)
  {
       //(<h:Token)[\S\s]*(/h:Token>)
       String RegExpression = String.Format(@"(<{0})[\S\s]*(/{0}>)", element);
       var replacedXml = Regex.Replace(xml, RegExpression, "<NewNode>TEST</NewNode>", RegexOptions.Multiline);
       return replacedXml;
  }

  Thanks,
  
  

  Abidali

  regex

• • Reply
  Kevin Shen -...

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  2777 Posts

  Re: Issue with replacing xml nodes

  Jul 10, 2014 04:51 AM|Kevin Shen - MSFT|LINK

  Hi Chithra_lyer,

  First ,I add your xml file to my project ,it hint me that the xml is not valid.

  Second, you can use linq to xml to get the entire node. and replace your Token node with other's value.

  I write a sample for you:

  here is my test.xml file:

  <?xml version="1.0" encoding="utf-8"?>
  <w:test xmlns:w="http://schemas.microsoft.com/office/word/2003/wordml">
    <w:DocumentProperties>
      <Title>title</Title>
      <Author>xyz</Author>
      <LastAuthor>pqr</LastAuthor>
    </w:DocumentProperties>
  </w:test>

  Below you can  find DocumentPropertites , and replace the value in the subnode in it.

  for example ,set the  Title value from "title" to "hello".

              // load the xml to memory
              XElement ex = XElement.Load(Server.MapPath("test.xml"));
              //get the namespace  in your xml file,so that you can find the DocumentProperties
              XNamespace xn = ex.GetNamespaceOfPrefix("w");
  
             //find all the Elements in w:DocumentProperties Node.
              IEnumerable<XElement> q = from ele in ex.Elements(xn + "DocumentProperties")
                                        select ele;
  
              foreach (XElement x in q.Elements())
              {
                   //find the Title Node
                  if (x.Name == "Title") {
                      //set value to Title node
                      x.Value = "hello";
                  }
              }
              ex.Save(Server.MapPath("test.xml"));
          }

  More details ,please refer to the link below:

  http://msdn.microsoft.com/en-US/us-en/library/bb387098.aspx

  Best Regards,

  Kevin Shen.

  Please Mark as Answer If it help you,thanks