xpath how to find node with max attribute value

Hi guys

can any one tell what would be xpath to find node with max value of val attribute i.e. <node val="4" />

<root>

</root>

Thank you,

Re: xpath how to find node with max attribute value

Hey

you can try somethine like this:

         XmlDocument xmlDoc = new XmlDocument();
        xmlDoc.LoadXml(file);
        XmlNodeList nodeList = xmlDoc.SelectNodes("root/node");

        foreach (XmlNode xmlNode in nodeList)
        {
          string strName = xmlNode.Attributes["val"].Value;
          int intStatsValue = Convert.ToInt32(xmlNode.InnerText);

//now you can store and compare the values
}

Hope this helps.

Please don't forget to "Mark as Answer" if this post answered your question.

Re: xpath how to find node with max attribute value

Thank you for the repsonse. But don't we have any xpath or xslt functions to acheive that.

Thanks,

Re: xpath how to find node with max attribute value

kalvagadda

Thank you for the repsonse. But don't we have any xpath or xslt functions to acheive that.

Thanks,

KK

In XPath try this:

/root/node[not(@val <= preceding-sibling::node/@val) and not(@val <=following-sibling::node/@val)]

Re: xpath how to find node with max attribute value

Have a look into this link. It uses a function math:max. It has a link for source for that function and explains how it can be implemented

http://www.exslt.org/math/functions/max/index.html

Hope this helps you

Re: xpath how to find node with max attribute value

Hi,

Thanks for the reply. It was very helpful.

Thanks,

Kiran