# How to divide an integer by an integer and yield a decimal RSS

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Last post Aug 31, 2004 03:22 PM by thuhue

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### How to divide an integer by an integer and yield a decimal

If we divide an integer by another integer, the result in C# is always an integer. How can we make the result to be 2 decimal? For example: 77 / 21 = 3.67 Thanks.

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### Re: How to divide an integer by an integer and yield a decimal

Convert the integers to decimal:
```int i = 77;
int j = 21;
decimal d = (decimal)i / (decimal)j;```
Jim ThoughtWorks

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### Re: How to divide an integer by an integer and yield a decimal

Thanks, that's what I found too. But the decimal needs to be formatted to 2 decimal. Otherwise it would show as a long bunch of decimals. Specifically how do we format a long decimal to "999.99" in C#? (We know how to do it in VB) Thanks.

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### Re: How to divide an integer by an integer and yield a decimal

This is just saying for hell of saying, but you *could* always overload the \ operator. *grin*
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### Re: How to divide an integer by an integer and yield a decimal

"you *could* always overload the \ operator" Overloads are attached to types, though. You can only overload operators on types that you control! Jim ThoughtWorks

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### Re: How to divide an integer by an integer and yield a decimal

"how do we format a long decimal to "999.99"" Use the ToString() overload with a format specifier. Something like (off the top of my head): myDecimal.ToString("#.00"); Jim ThoughtWorks

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### Re: How to divide an integer by an integer and yield a decimal

Also look at Math.Round, unfortunatly i think it only supports the double type in version 1.1 and decimal support is added in v2 Dave Legg
Dave Legg

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### Re: How to divide an integer by an integer and yield a decimal

I found it: myDecimal.ToString("N2"); Thanks.

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### Re: How to divide an integer by an integer and yield a decimal

To be honest, isn't the decimal type overkill if you are going for two places of precision when dividing an integer by an integer?
Picky

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### Re: How to divide an integer by an integer and yield a decimal

What we did here was for getting a decimal when one integer dividing another yields a decimal value such as 7/3=2.33, not a rounded integer. Thanks.

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### Re: How to divide an integer by an integer and yield a decimal

::Overloads are attached to types, though. You can only overload operators on types that you control! Jim, you're right, but you can control the output. you can return a different type. you can always overload the / for int,int to return a decimal type, and do the casting in the overloaded operator.
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### Re: How to divide an integer by an integer and yield a decimal

I realize the casting was done to retain the decimal amount, but I think a double would suffice.
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### Re: How to divide an integer by an integer and yield a decimal

22/7... put that in a double. :)
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### Re: How to divide an integer by an integer and yield a decimal

"you can always overload the / for int,int to return a decimal type" And how would you do that? Jim ThoughtWorks

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### Re: How to divide an integer by an integer and yield a decimal

Kragie, they just want two decimal places.
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### Re: How to divide an integer by an integer and yield a decimal

Jim, I didn't say it's going to be easy. Or that it was a good solution. I just said it was "possible". Just create an object that is essentially a decimal, and start creating a crapload of overloaded operators. Now. I'll admit that the original post was done in bad taste for humor, but still. It "is" possible. I'd be the first to slap someone that wanted to do it like that, but that wasn't the purpose of my initial post here.
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