repeated item should not be added to the listbox RSS

• • Reply
  

  anigova

  Member

  6 Points

  19 Posts

  repeated item should not be added to the listbox

  Jan 10, 2013 08:52 AM|LINK

  Hi

  I have two Listbox controls,among one contains list of items when i select one item in listbox1 that item ll be added to listbox2.If I select the same item again it ll give a message like item already exists and that same item should not appear in my listbox2.

  I did this, but its (duplicate item ) including in listbox2

• • Reply
  

  ManikandanUl...

  Participant

  850 Points

  253 Posts

  Re: repeated item should not be added to the listbox

  Jan 10, 2013 09:02 AM|LINK

  pls refer this below code. Its working fine.

    protected void btnMoveRight_Click(object sender, EventArgs e)
      {
          try
          {
              ArrayList txnMoved = new ArrayList();
              if (string.IsNullOrEmpty(lstTxnLeft.SelectedValue))
              {
                  lblErrMsg.Visible = true;
                  lblErrMsg.Text = "Select any Transaction to MoveRight";
              }
              else
              {
                  lblErrMsg.Visible = false;
                  for (int i = lstTxnLeft.Items.Count - 1; i >= 0; i--)
                  {
                      if (lstTxnLeft.Items[i].Selected == true)
                      {
                          lstTxnRight.Items.Add(lstTxnLeft.Items[i]);
                          ListItem li = lstTxnLeft.Items[i];
                          string txnMval = lstTxnLeft.Items[i].Value.ToString();
                          lstTxnLeft.Items.Remove(li);
  
                          if (Session["delTxn"] != null)
                          {
                              txnMoved = (ArrayList)Session["delTxn"];
                              if (txnMoved.Contains(txnMval))
                              {
                                  txnMoved.Remove(txnMval);
                                  Session["delTxn"] = txnMoved;
                              }
                          }                       
                      }
                  }
              }
          }
          catch (Exception ex)
          {
              log.ErrorFormat("Txns_MoveRight ended with exception:", ex);
          }
      }
  
      protected void btnMoveLeft_Click(object sender, EventArgs e)
      {
          try
          {
              ArrayList delTxn1 = new ArrayList();
              if (string.IsNullOrEmpty(lstTxnRight.SelectedValue))
              {
                  lblErrMsg.Visible = true;
                  lblErrMsg.Text = "Select any Transaction to MoveLeft";
              }
              else
              {
                  lblErrMsg.Visible = false;
                  for (int i = lstTxnRight.Items.Count - 1; i >= 0; i--)
                  {
                      if (lstTxnRight.Items[i].Selected == true)
                      {
                          lstTxnLeft.Items.Add(lstTxnRight.Items[i]);
                          ListItem li = lstTxnRight.Items[i];
  
                          string deleteTxns = lstTxnRight.Items[i].Value.ToString();
                          lstTxnRight.Items.Remove(li);
  
                          if (Session["delTxn"] != null)
                          {
                              delTxn1 = (ArrayList)Session["delTxn"];
                          }
                          delTxn1.Add(deleteTxns);
                          Session["delTxn"] = delTxn1;
                      }
                  }
              }
          }
          catch (Exception ex)
          {
              log.ErrorFormat("Txns_MoveLeft ended with exception:", ex);
          }
      }

  Manikandan Ulagu
  Click "…Mark As Answer" if my reply helpful....
  
  
• • Reply
  

  urenjoy

  Star

  11997 Points

  1797 Posts

  Re: repeated item should not be added to the listbox

  Jan 10, 2013 09:04 AM|LINK

  Try this...

  http://geekswithblogs.net/dotNETvinz/archive/2009/02/24/moving-listitems-between-two-listbox--server-side-approach.aspx

  http://techbrij.com
• • Reply
  

  chandrasheka...

  Star

  10258 Points

  1760 Posts

  Re: repeated item should not be added to the listbox

  Jan 10, 2013 09:15 AM|LINK

  Hi

  Try the below:

  <asp:ListBox ID="ListBox1" runat="server" AutoPostBack="true" SelectionMode="Multiple"
              OnSelectedIndexChanged="ListBox1_SelectionChanged">
              <asp:ListItem Text="A" Value="1"></asp:ListItem>
              <asp:ListItem Text="B" Value="2"></asp:ListItem>
              <asp:ListItem Text="C" Value="3"></asp:ListItem>
              <asp:ListItem Text="D" Value="4"></asp:ListItem>
          </asp:ListBox>
          <asp:ListBox ID="ListBox2" runat="server">
              <asp:ListItem Text="Select" Value="-1"></asp:ListItem>
          </asp:ListBox>
          <br />
          <asp:Label ID="lblError" runat="server" ForeColor="Red" Text="Item already in the list. Please select a new one."
              Visible="false"></asp:Label>

  
  
  

  Code:

   protected void ListBox1_SelectionChanged(object sender, EventArgs e)
          {
              if (ListBox2.Items.FindByText(ListBox1.SelectedItem.Text) == null)
              {
                  lblError.Visible = false;
                  ListBox2.ClearSelection();
                  ListBox2.Items.Add(ListBox1.SelectedItem);
              }
              else
              {
                  lblError.Visible = true;
              }
          }

  
  
  

  YCS
  Please try the answer for the post and finally Don't forget to click “Mark as Answer” on the post that helped you.
  
  • Marked as answer by anigova on Jan 10, 2013 10:50 AM
• • Reply
  

  anigova

  Member

  6 Points

  19 Posts

  Re: repeated item should not be added to the listbox

  Jan 10, 2013 10:51 AM|LINK

  @chandrashekar: Thank u..its working now.......