File Upload query to create new directory within another ? RSS

• • Reply
  

  prontonet

  Member

  243 Points

  484 Posts

  File Upload query to create new directory within another ?

  May 03, 2012 10:33 AM|LINK

  hi,

  I am using System.IO to upload multiple files. I am still trying to get the code working

  but having no luck.

  Objective

  On my File Server I have a Directory Called "Users".

  On my aspx page, I have a FORM that gets info from a new user.

  I now want to save the images in the "Users" Directory and within that create

  another Directory Called The "Name" of the user - taken from the "Name" Textbox

  on the form. 

  Inconplete Code

      string name= Name.Text; // (variable from form)
  
  
  
  
  
  
  
          HttpFileCollection uploadedFiles = Request.Files;
  
          for (int i = 0; i < uploadedFiles.Count; i++)
          {
  
  
              HttpPostedFile file = uploadedFiles[i];
              string fileExt = Path.GetExtension(file.FileName).ToLower();
              string fileName = Path.GetFileName(file.FileName);
              if (fileName != string.Empty)
              {
                  try
                  {
                      
                          if (!Directory.Exists(Server.MapPath("/Users/")))
                          {
  
                              {
  
                                  Directory.CreateDirectory(Server.MapPath("/Users/"));
  
                              }
  
                           
                           
                              
                              
                         
  
  
                          }
  
                          else
                          {
  
                          }
                  }
                  catch (Exception ex)
                  {
                      throw ex;
                  }
              }
  
          }

• • Reply
  

  kedarrkulkar...

  All-Star

  34421 Points

  5534 Posts

  Re: File Upload query to create new directory within another ?

  May 03, 2012 10:53 AM|LINK

  try this

          string name= Name.Text; // (variable from form)

          HttpFileCollection uploadedFiles = Request.Files;
          for (int i = 0; i < uploadedFiles.Count; i++)
          {
              HttpPostedFile file = uploadedFiles[i];
              string fileExt = Path.GetExtension(file.FileName).ToLower();
              string fileName = Path.GetFileName(file.FileName);
              if (fileName != string.Empty)
              {
                  try
                  {                  
                      if (!Directory.Exists(Server.MapPath("/Users/")))
                      {
                          Directory.CreateDirectory(Server.MapPath("/Users/"));
                      }
                      if (!Directory.Exists(Server.MapPath("/Users/name")))
                      {
                          Directory.CreateDirectory(Server.MapPath("/Users/name"));
                      }
                      file.PostedFile.SaveAs(Server.MapPath("/Users/name") + "/" + file.FileName);

                  }
                  catch (Exception ex)
                  {
                      throw ex;
                  }
              }

          }

  hope this helps...

  Cheers!
  KK
  
  Please mark as Answer if post helps in resolving your issue
  My Site
  • Marked as answer by prontonet on May 03, 2012 11:35 AM
• • Reply
  

  ramiramilu

  All-Star

  95463 Points

  14106 Posts

  Re: File Upload query to create new directory within another ?

  May 03, 2012 11:02 AM|LINK

    if (!Directory.Exists(Server.MapPath("/Users/")))
                          {
                                  Directory.CreateDirectory(Server.MapPath("/Users/"));

                                  // Save File here in the new directory...uploadedFiles[i].SaveAs(your file name);

                          }
  
                          else
                          {
                                  // As already directory exists, save file in the directory...uploadedFiles[i].SaveAs(your file name);
                          }

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