Reply

asante_za

Member

16 Points

113 Posts

Re: Condition in Cookie

Apr 29, 2012 10:14 AM|LINK

I have updated the code and now getting the error below:

Server Error in '/QuestLocal' Application.

Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.
Exception Details: System.ArgumentOutOfRangeException: Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index
Source Error:

Line 21:                 for (int j = 0; (j <= rbl.Items.Count); j++)
Line 22:                 {
Line 23: if ((rbl.Items[j].Value == "4")) Line 24:                     {
Line 25:                         if (Request.Cookies["Q1"] != null)

Source File: c:\inetpub\wwwroot\QuestLocal\Q1.aspx.cs Line: 23

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;

public partial class _Default : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {

    }
    protected void Button3_Click(object sender, EventArgs e)
    {
        foreach (DetailsViewRow gvr in DetailsView1.Rows)
        {
            if ((gvr.RowType == DataControlRowType.DataRow))
            {
                RadioButtonList rbl = ((RadioButtonList)(gvr.FindControl("RadioButtonList1")));
                for (int j = 0; (j <= rbl.Items.Count); j++)
                {
                    if ((rbl.Items[j].Value == "4"))
                    {
                        if (Request.Cookies["Q1"] != null)
                        {
                            Response.Cookies["Q1"].Value = Label2.Text.ToString();
                            Response.Redirect("../QuestLocal/Q2.aspx");
                        }
                        else
                        {
                            if (Request.Cookies["Q1"] != null)
                            {
                                Response.Cookies["Q1"].Value = Label2.Text.ToString();

                                Response.Redirect("../QuestLocal/Q3.aspx");
                            }
                        }
                    }
                }
            }
        }
    }

Reply

AmalO.Abdull...

Contributor

3116 Points

764 Posts

Re: Condition in Cookie

Apr 29, 2012 10:31 AM|LINK

try

for (int j = 0; j <= rbl.Items.Count-1; j++)

Please "Mark as Answer" if this post helps.Thank You :)

Reply

asante_za

Member

16 Points

113 Posts

Re: Condition in Cookie

Apr 29, 2012 11:02 AM|LINK

Changed as suggested,

for (int j = 0; j <= rbl.Items.Count-1; j++)

No error, but stuck in Q1. Doesn't move on when the button is clicked.

Reply

AmalO.Abdull...

Contributor

3116 Points

764 Posts

Re: Condition in Cookie

Apr 29, 2012 11:32 AM|LINK

you are stuck there because you haven't change the code as i told you !!!

if ((rbl.Items[j].Value == "4"))
                    {
                        if (Request.Cookies["Q1"] != null)
                        {
                            Response.Cookies["Q1"].Value = Label2.Text.ToString();
                            Response.Redirect("../QuestLocal/Q2.aspx");
                        }
                    }
else
{

                            if (Request.Cookies["Q1"] != null)
                            {
                                Response.Cookies["Q1"].Value = Label2.Text.ToString();

                                Response.Redirect("../QuestLocal/Q3.aspx");
                            }
}

make the else for the first if not the second

Please "Mark as Answer" if this post helps.Thank You :)

Reply

asante_za

Member

16 Points

113 Posts

Re: Condition in Cookie

Apr 29, 2012 11:46 AM|LINK

Hi Amal, Attached is what I have done but still stuck. Kindly do the changes on the code for me.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;

public partial class _Default : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {

    }
    protected void Button3_Click(object sender, EventArgs e)
    {
        foreach (DetailsViewRow gvr in DetailsView1.Rows)
        {
            if ((gvr.RowType == DataControlRowType.DataRow))
            {
                RadioButtonList rbl = ((RadioButtonList)(gvr.FindControl("RadioButtonList1")));
                for (int j = 0; j <= rbl.Items.Count-1; j++)
                {
                    if ((rbl.Items[j].Value == "5"))
                    {
                        if (Request.Cookies["Q1"] != null)
                        {
                            Response.Cookies["Q1"].Value = Label2.Text.ToString();
                            Response.Redirect("../QuestLocal/Q2.aspx");
                        }
                    }
                        else
                        {
                            if (Request.Cookies["Q1"] != null)
                            {
                                Response.Cookies["Q1"].Value = Label2.Text.ToString();

                                Response.Redirect("../QuestLocal/Q3.aspx");
                            }
                        }
                    }
                }
            }
        }

Reply

AmalO.Abdull...

Contributor

3116 Points

764 Posts

Re: Condition in Cookie

Apr 29, 2012 11:58 AM|LINK

hey iam sorry maybe you should change this

if ((rbl.Items[j].Value == "5")) to

if( rbl.selectedValue.toString () == "5")

and no need for the for loop ,,, i missundertood you from the begining so the code will be withour the for loop as follows

  if ((rbl.selectValue.toString() == "5"))
  {
      if (Request.Cookies["Q1"] != null)
            {
                        Response.Cookies["Q1"].Value = Label2.Text.ToString();
                        Response.Redirect("../QuestLocal/Q2.aspx");
            }
   }
else
    {
       if (Request.Cookies["Q1"] != null)
             {
                       Response.Cookies["Q1"].Value = Label2.Text.ToString();

                       Response.Redirect("../QuestLocal/Q3.aspx");
               }
      }

Please "Mark as Answer" if this post helps.Thank You :)

Marked as answer by asante_za on Apr 29, 2012 01:30 PM

Reply

asante_za

Member

16 Points

113 Posts

Re: Condition in Cookie

Apr 29, 2012 12:15 PM|LINK

No errors, but still stuck. See full code attached.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;

public partial class _Default : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {

    }
    protected void Button3_Click(object sender, EventArgs e)
    {
        foreach (DetailsViewRow gvr in DetailsView1.Rows)
        {
            if ((gvr.RowType == DataControlRowType.DataRow))
            {
                RadioButtonList rbl = ((RadioButtonList)(gvr.FindControl("RadioButtonList1")));
               
                {
                    if ((rbl.SelectedValue.ToString() == "5"))

                    {
                        if (Request.Cookies["Q1"] != null)
                        {
                            Response.Cookies["Q1"].Value = Label2.Text.ToString();
                            Response.Redirect("../QuestLocal/Q2.aspx");
                        }
                    }
                        else
                        {
                            if (Request.Cookies["Q1"] != null)
                            {
                                Response.Cookies["Q1"].Value = Label2.Text.ToString();

                                Response.Redirect("../QuestLocal/Q3.aspx");
                            }
                        }
                    }
                }
            }
        }

Reply

AmalO.Abdull...

Contributor

3116 Points

764 Posts

Re: Condition in Cookie

Apr 29, 2012 12:19 PM|LINK

can i see you aspx page please? and what do u mean its stuck ??

do u mean it always goes to q2 , you mean always the value is 5?

try to change from selectedValue to selectedText

Please "Mark as Answer" if this post helps.Thank You :)

Reply

asante_za

Member

16 Points

113 Posts

Re: Condition in Cookie

Apr 29, 2012 01:29 PM|LINK

Works perfectly now obeying all conditions! Weldone Amal, and thank you very, very much. I do not see anything I have done to the code attached. Congratulations once more.

protected void Button3_Click(object sender, EventArgs e)
    {
        foreach (DetailsViewRow gvr in DetailsView1.Rows)
        {
            if ((gvr.RowType == DataControlRowType.DataRow))
            {
                RadioButtonList rbl = ((RadioButtonList)(gvr.FindControl("RadioButtonList1")));
               
                {
                    if ((rbl.SelectedValue.ToString() == "5"))

                    {
                        if (Request.Cookies["Q1"] != null)
                        {
                            Response.Cookies["Q1"].Value = Label2.Text.ToString();
                            Response.Redirect("../QuestLocal/Q2.aspx");
                        }
                    }
                        else
                        {
                           if (Request.Cookies["Q1"] != null)
                            {
                                Response.Cookies["Q1"].Value = Label2.Text.ToString();

                                Response.Redirect("../QuestLocal/Q3.aspx");
                            }
                       
                        }
                    }
                }
            }
        }

Reply

AmalO.Abdull...

Contributor

3116 Points

764 Posts

Re: Condition in Cookie

Apr 29, 2012 01:42 PM|LINK

thank you asante ,, that's my pleasure to help you :)

Please "Mark as Answer" if this post helps.Thank You :)

Condition in Cookie RSS

30 replies

asante_za

Re: Condition in Cookie

Server Error in '/QuestLocal' Application.

Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index

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