Visual Basic .NET

Re: Problem Calling Function A In Funtion A

mmmisa83 — Mon, 06 Jul 2009 00:28:26 GMT

Ah, I think you are right. Your first reply suggests to change line 16 to

Return RandomizeNo(totalLot)

but what I did was changing line 19 with the suggested code. That's why it caused infinite looping LOL.

Yes, both snippets below work.

If randomizeAgain = True Then
  Return RandomizeNo(totalLot)
End If

  Return intLot

If randomizeAgain = True Then
  Return RandomizeNo(totalLot)
Else
  Return intLot
End If

Actually I modified/simplified the function a bit to make it easier for readers to see the function flow. I just wanted to mention the function calling in the function assuming readers would ignore the For Looping part.

Well it works now! Just by adding the word 'Return' in line 16 ;)

Thanks a lot.

Re: Problem Calling Function A In Funtion A

anders__f — Sun, 05 Jul 2009 12:44:19 GMT

Well, it would only call the function again if randomizeAgain = True, and randomizeAgain is only set to true if intLot = 5. Isn't that what you want?

These code snippets are equivalent:

If randomizeAgain = True Then
    Return RandomizeNo(totalLot)
End If

Return intLot

If randomizeAgain = True Then
    Return RandomizeNo(totalLot)
Else
    Return intLot
End If

Just another thing, why do you use a for loop? The looping variable k is never used. And this in turn means that the parameter totalLot is in fact never used. What exactly do you want this function to return for different parameter values?

Re: Problem Calling Function A In Funtion A

mmmisa83 — Sun, 05 Jul 2009 12:33:47 GMT

Thanks anders__f for replying. But I dont think that would solve the problem, it instead will cause infinite looping because "Return RandomizeNo(totalLot)" keeps calling the function.

This function returns intLot, if the value of intLot is not 5. Otherwise the function will be called.

Any other suggestion? Thanks again.

Re: Problem Calling Function A In Funtion A

anders__f — Sun, 05 Jul 2009 11:35:05 GMT

Look at the exit point for this function, the return statement at line 19. It will always return intLot, no matter if line 16 was executed or not.

The thing is that when you call the function again in line 16, you will get a new variable scope, and the function will not use the same variable/values as in the calling scope.

I have not tried your code, but probably it will be enough to change line 16 to

Return RandomizeNo(totalLot)

Problem Calling Function A In Funtion A

mmmisa83 — Sun, 05 Jul 2009 08:13:29 GMT

Hi,

I have this simple function (below) that randomizes number between 1 to 10.

This function works well, except when Random() returns 5, which means intLot=5, randomizeAgain = true, and then the same function RandomizeNo will be called to randomize again. (refer the code below)

Even the new value of intLot equals other than 5 next time, say 4, the funtion returns 0.

I have no idea why.

Function RandomizeNo(ByVal totalLot As Integer) As Integer
        Dim intLot As Integer

        randomizeAgain = False
        
	intLot = New Random().Next(1, 10)

	For k = 1 To totalLot - 1
	  If intLot = 5 Then
	    randomizeAgain = True
	    Exit For
	  End If
	Next

        If randomizeAgain = True Then
            RandomizeNo(totalLot)
        End If

        Return intLot
End Function

Please help.

Thanks in advance.