Visual Basic .NET

Re: str.split() help

RatheeshC — Mon, 29 Jun 2009 21:21:50 GMT

Hi,

To extract the number from "images/test/89" try this

string mystr = "images/test/89";

string Id = mystr.Substring(mystr.LastIndexOf("/") + 1);

To extract the ".jpg" try this

mystr = "lddmen.jpg";
string ext = mystr.Substring( mystr.IndexOf("."));

Thanks

Re: str.split() help

jeffiec — Mon, 29 Jun 2009 21:00:30 GMT

Dim trmst As Char() = {"."c, "j"c, "p"c, "g"c}

imagename = imagename.TrimEnd(trmst)

that got the first part working, tryed remove to remove the dir path and got this error.

id = id.Remove(0, 20)

Index and count must refer to a location within the string. Parameter name: count

After searching, it apears that it reads it as empty? how can it be empty?

Re: str.split() help

jeffiec — Mon, 29 Jun 2009 17:57:31 GMT

works great! thank you,
now i need to strip the 89 off of "images/featured/89" this could be 1, 2, 3 or even 4 numbers, so the qualifier would be the 2nd "/" ?
also need to strip ".jpg" off the 2nd string, "." as the qualifier?

imagename = imagename.Substring(imagename.TrimEnd(".jpg"))
doesnt seem to work

thanks again for help so far. :)

Re: str.split() help

ramireddyindia — Mon, 29 Jun 2009 14:59:44 GMT

string mystr = "images/test/89lddmen.jpg";
string ImageName = mystr.Substring(mystr.IndexOf("ld"));
string Id = mystr.Substring(mystr.LastIndexOf("/")+1).Replace(ImageName, "");

str.split() help

jeffiec — Mon, 29 Jun 2009 14:12:11 GMT

I need to split up a string to get some string data, string like "images/test/89lddmen.jpg".

there will always be number at the beginning, anywhere between 1 and 5000, the first two characters after the number will always begin with"ld", so i can always look for those two chars to split, only thing is i can get it to work.

dim mystr as string
dim strar() as string
mystr="images/test/89lddmen.jpg"
strar.split(mystr,'ld')

expected results would be:
strar(0)="89"
strat(1)="lddmen.jpg"

then need to trim the ".jpg" off the end :D
dont think im forming it corectly though or not too sure of the overflow.

thanks in advance.