How Get the response value from URL RSS

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  aravindhrm

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  3 Posts

  How Get the response value from URL

  Dec 18, 2012 01:35 AM|LINK

  hi all,

  i have send the parameter to query string and it will return value like 0 or 1 or 2.

  how can i get this value ? please help me

  example:

  https://api.twitter.com/1/users/profile_image?screen_name=twitterapi&size=bigger

  it shows 1

  how can i get this "1"

  • Edited by aravindhrm on Dec 18, 2012 01:35 AM
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  oned_gk

  All-Star

  31820 Points

  6510 Posts

  Re: How Get the response value from URL

  Dec 18, 2012 01:58 AM|LINK

  try

  string urlstr;
          urlstr = "https://api.twitter.com/1/users/profile_image?screen_name=twitterapi&size=bigger";
          urlstr = urlstr.Replace("https://api.twitter.com/", "");
          string valstr;
          valstr = urlstr.Split(new char[]{'/'}).First();

  Programming to simplify, dont look for hard way
  • Marked as answer by Amy Peng - MSFT on Dec 25, 2012 06:50 AM
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  hafizzeeshan

  Participant

  834 Points

  253 Posts

  Re: How Get the response value from URL

  Dec 18, 2012 02:38 AM|LINK

  hi

             please Check following

  string tst = Request.QueryString["parametername"];

  Thanks
  Zeeshan Rauf
  # 92-3216698206
  Email : zeeshan_rouf@hotmail.com
  Please mark the replies as answers if they help or unmark if not.
  
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  matifnadeem

  Contributor

  4758 Points

  1130 Posts

  Re: How Get the response value from URL

  Dec 18, 2012 05:04 AM|LINK

  aravindhrm

  example:

  https://api.twitter.com/1/users/profile_image?screen_name=twitterapi&size=bigger

  it shows 1

  how can i get this "1"

  Hi aravindhrm,

  You can acheive any number either it is 1,2,3 or anything else by using substring method.

  Checkout my code

  string url = "https://api.twitter.com/1/users/profile_image?screen_name=twitterapi&size=bigger";
  int index = url.IndexOf(".com");                        
  int returnValue = Convert.ToInt32(url.Substring(index + 5, 1));
  Console.WriteLine(returnValue);

  Let me know if any query remains.

  Cheers

  
  M Atif Nadeem
  Mark as Answer if you got right thing
  Read my blog | Follow me on LinkedIn
  • Marked as answer by Amy Peng - MSFT on Dec 25, 2012 06:50 AM