@html.actionlink with @html.displayfor RSS

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  aspmunkee

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  6 Points

  29 Posts

  @html.actionlink with @html.displayfor

  Jul 22, 2012 08:20 AM|LINK

  Hi all got myself confused with this syntax

  I wish to create a list of items and allow each item to be clickable to send me to a new controller action.

  The basic format of the list is handled via:

  <h2>Departments</h2>
  <ul>
  @foreach (var item in Model.Departments)
  {
  <li>@Html.DisplayFor(items => item.DepartmentName)</li>
  }
  </ul>

  How do I go about implementing html.actionlink in to this with a query parameter of the department ID. I thought the following would be ok:

  <h2>Departments</h2>
  <ul>
  @foreach (var item in Model.Departments)
  {
  <li>@Html.DisplayFor(items => Html.ActionLink(item.DepartmentName,"Index","DepartmentOverview",new{dept=item.DepartmentID}))</li>  
  }
  </ul>

  But no luck I get the error:

  Templates can be used only with field access, property access, single-dimension array index, or single-parameter custom indexer expressions.

  Any ideas?

  • Edited by aspmunkee on Jul 22, 2012 08:21 AM
  • Edited by aspmunkee on Jul 22, 2012 08:21 AM
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  Mudasir.Khan

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  3142 Posts

  Re: @html.actionlink with @html.displayfor

  Jul 22, 2012 10:58 AM|LINK

  try

  @foreach (var item in Model.Departments)
  {
  <li> Html.ActionLink(item.DepartmentName, new{ action="index",dept=item.DepartmentID})</li>  
  }

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• • Reply
  

  Mudasir.Khan

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  15346 Points

  3142 Posts

  Re: @html.actionlink with @html.displayfor

  Jul 22, 2012 10:58 AM|LINK

  for reference please check this

  http://weblogs.asp.net/scottgu/archive/2007/11/13/asp-net-mvc-framework-part-1.aspx

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  aspmunkee

  Member

  6 Points

  29 Posts

  Re: @html.actionlink with @html.displayfor

  Jul 22, 2012 01:40 PM|LINK

  <li>@Html.ActionLink(item.DepartmentName, "index","DepartmentOverview", new { dept = item.DepartmentName },null)</li>

  This is what worked in the end. Thanks for the ref

  • Marked as answer by aspmunkee on Jul 22, 2012 01:40 PM