How to call a URL(script) after post RSS

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  being_mp

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  How to call a URL(script) after post

  Feb 21, 2012 12:16 PM|LINK

  Hi there, got following problem: I want to upload a large amount of image data to the server. Once this is done, I need to start a script on the server to process the data (in this case, it's python). I could start the script with a parameterized call. So my question is, how would I build the url and send it automatically after the upload is complete. I'm using if(IsPost) and a counter to upload the images. I think I can not use the action parameter in the form tag. Am i right?

  Thanks for the help.

  post url upload

  • Edited by being_mp on Feb 21, 2012 12:16 PM
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  smirnov

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  Re: How to call a URL(script) after post

  Feb 21, 2012 05:21 PM|LINK

  Can't you just use a redirect from the code behind?

  Response.Redirect("script.py");

  • Edited by smirnov on Feb 21, 2012 05:21 PM
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  being_mp

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  Re: How to call a URL(script) after post

  Feb 21, 2012 06:52 PM|LINK

  I have to send a few parameters from user-input to the script. I think that's not possible with the redirect.

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  smirnov

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  Re: How to call a URL(script) after post

  Feb 22, 2012 01:59 AM|LINK

  If script accepts parameters from a query string, use "script.py?x=1&y=2". In other case, use HTTP POST

  string url = "http://...";
  HttpWebRequest req = (HttpWebRequest)WebRequest.Create(url);
  string proxy = null;
  
  string data = String.Format("parameter1={0}&parameter2={1}&parameter3={2}", parameter1, parameter2, parameter3);
  byte[] buffer = Encoding.UTF8.GetBytes(data);
  
  req.Method = "POST";
  req.ContentType = "application/x-www-form-urlencoded";
  req.ContentLength = buffer.Length;
  req.Proxy = new WebProxy(proxy, true); // ignore for local addresses
  req.CookieContainer = new CookieContainer(); // enable cookies
  
  Stream reqst = req.GetRequestStream(); // add form data to request stream
  reqst.Write(buffer, 0, buffer.Length);
  reqst.Flush();
  reqst.Close();
  
  HttpWebResponse res = (HttpWebResponse)req.GetResponse();
  
  Stream resst = res.GetResponseStream();
  StreamReader sr = new StreamReader(resst);
  string response = sr.ReadToEnd();

  Hope this helps.

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  being_mp

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  Re: How to call a URL(script) after post

  Feb 22, 2012 08:16 AM|LINK

  Thank you for your help. I'm new in programming, so sorry for my questions. I got an error in the following three lines: (the name encoding is not  available in the actual context...)

  byte[] buffer = Encoding.UTF8.GetBytes(data);

  req.ContentLength = buffer.Length;

  reqst.Write(buffer, 0, buffer.Length);

  Is there a possibility to set up a simple site to test, how the post gets submitted?

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  rabindra_lal

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  Re: How to call a URL(script) after post

  Feb 22, 2012 08:20 AM|LINK

  Please visit this link

  http://msdn.microsoft.com/en-us/magazine/cc163941.aspx

  post url upload

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  smirnov

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  Re: How to call a URL(script) after post

  Feb 22, 2012 01:38 PM|LINK

  You need to add system.text namespace in your class.

  using System.Text;

  Regarding test script. Suppose you're posting a variable called "username"

  If using .cgi

  import cgi
  form = cgi.FieldStorage()
  print form["username"]

  if using .py:

  form = web.input()
  print form.username

  • Edited by smirnov on Feb 22, 2012 01:43 PM
  • Marked as answer by Dino He - MSFT on Feb 28, 2012 01:51 AM