open several new pages on button click

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open several new pages on button click

Last post 09-15-2009 5:17 AM by Shengqing Yang - MSFT. 8 replies.

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open several new pages on button click

09-14-2009, 2:27 AM

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496 point Member
Roba
Member since 11-17-2008, 7:29 AM
Posts 182

hi,

i have a situation on which i want to open several pages on one button click

i has three checkboxes and one button ...for every checkbox i choose i have to open a new page when i click the button ...is there a way i can do such an approach ?

thanks in advance

Re: open several new pages on button click

09-14-2009, 5:56 AM

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387 point Member
Mohammed.Hassan
Member since 07-12-2009, 10:39 AM
Posts 70

In the click event handler of the button, check which pages should be open and call a javascript function to open these pages using window.open() function

You can call this javascript function using RegisterClientScriptBlock function

Please Mark As Answer if my post helps you
Thanks

Re: open several new pages on button click

09-14-2009, 11:42 PM

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29,782 point All-Star
Shengqing Yang - MSFT
Member since 05-06-2008, 4:56 AM
Posts 1,904

Roba:

Hi,

i have a situation on which i want to open several pages on one button click

i has three checkboxes and one button ...for every checkbox i choose i have to open a new page when i click the button ...is there a way i can do such an approach ?

thanks in advance

Hi,

We can easily use JavaScript function to achieve this task. Please refer to the demo below to see if it meets your requirement.

<%@ Page Language="VB" %>

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title></title>
    <script type="text/javascript">
        function openForm() {
            if (document.getElementById("CheckBox1").checked == 1)
                window.open("http://www.bing.com");
            if (document.getElementById("CheckBox2").checked == 1)
                window.open("http://www.google.com");
            if (document.getElementById("CheckBox3").checked == 1)
                window.open("http://www.msn.com");
        }
    </script>
</head>
<body>
    <form id="form1" runat="server">
    <div>
        <asp:CheckBox ID="CheckBox1" runat="server" />www.bing.com<br />
        <asp:CheckBox ID="CheckBox2" runat="server" />www.google.com<br />
        <asp:CheckBox ID="CheckBox3" runat="server" />www.msn.com<br />
        <asp:Button ID="Button1" runat="server" Text="Button" OnClientClick="openForm();" />
    </div>
    </form>
</body>
</html>

Best Regards,
Shengqing Yang

Please remember to click “Mark as Answer” on the post that helps you, and to click “Unmark as Answer” if a marked post does not actually answer your question. This can be beneficial to other community members reading the thread : )

Re: open several new pages on button click

09-15-2009, 2:28 AM

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496 point Member
Roba
Member since 11-17-2008, 7:29 AM
Posts 182

Well i tried your way but when i click the button nothing happens .......plz help

<%@ Page Language="VB" AutoEventWireup="true" CodeFile="CLPrTranID.aspx.vb" Inherits="CLprtranID"
MasterPageFile="~/MasterPage.master" Title="PreTrans" Culture="en-GB" %>

<asp:Content runat="server" ContentPlaceHolderID="ContentPlaceHolder1" >
<div style="height: 354px; margin-top: 28px;">

<asp:CheckBox ID="ClmStatus" runat="server"
                style="position :absolute; top: 81px; left: 650px;" />
            <asp:CheckBox ID="Info" runat="server"
                style="position :absolute; top: 51px; left: 650px;" AutoPostBack="True" />
            <asp:CheckBox ID="MRpt" runat="server"
                style="position :absolute; top: 21px; left: 650px;" Checked="True" />
<asp:Button ID="Prt" runat="server" Text="Print Transaction"
                style="position : absolute; top: 334px; left: 18px; width: 134px; margin-top: 0px;"
                Font-Bold="True" OnClientClick="openForm();"/>
</div>
     <script type="text/javascript" language="javascript" >
         function openForm()
        {
            if (document.getElementById("MRpt").checked == 1)
                window.open("CLReport.aspx?type=M");
            if (document.getElementById("Info").checked == 1)
                window.open("CLReport.aspx?type=I&ClmTrs=" & document.getElementById("ClmTrs"));
            if (document.getElementById("ClmStatus").checked == 1)
                window.open("CLReport.aspx?type=S");
        }
    </script>

</asp:Content>

Re: open several new pages on button click

09-15-2009, 2:33 AM

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6,003 point Contributor
vijayst
Member since 12-19-2008, 10:49 AM
Posts 1,219

In your javascript, use document.getElementByID("<%= Mrpt.ClientID %>")

This is because your checkbox is rendered within a content control. and the ids rendered in HTML will change.

-Vijay
My blog: www.VijayT.com

Re: open several new pages on button click

09-15-2009, 3:28 AM

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1,184 point Participant
sureshkumar.gundala
Member since 07-16-2009, 9:33 AM
Bangalore
Posts 259

Hi Roba,

In your code

if (document.getElementById("MRpt").checked == 1).

Instead of double quotes use single quote. then it will work

if (document.getElementById('MRpt').checked == 1)

window.open("CLReport.aspx?type=M");

Also make sure that the pages CLReport.aspx already exists

Please click "Mark as Answer" if you think this post answer your question

Best Regards,
Suresh Kumar Gundala

Re: open several new pages on button click

09-15-2009, 3:53 AM

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1,547 point Participant
ashish-1983
Member since 09-14-2009, 7:29 AM
Posts 512

it should work..

can u tell us wot is an error?

Please remember to click "Mark as Answer" on the post that helps you.

Re: open several new pages on button click

09-15-2009, 4:03 AM

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496 point Member
Roba
Member since 11-17-2008, 7:29 AM
Posts 182

thanks ,

seems that this detail made it work

:D thank you very much

Re: open several new pages on button click

09-15-2009, 5:17 AM

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29,782 point All-Star
Shengqing Yang - MSFT
Member since 05-06-2008, 4:56 AM
Posts 1,904

Roba:

thanks,

seems that this detail made it work

:D thank you very much

Hi,

That's all right. Just as a note, the reason why your previous code didn't work is you used it in a Content Page. When the page runs, the JavaScript cannot find the CheckBox by its original name in a Content Page.

Best Regards,
Shengqing Yang

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