Hello All

i have 2 aspx pages first.aspx and second.aspx

first.aspx consists of a listbox.and  a button .

when button is clicked it goes to next page(i.e second.aspx)

Second.aspx is having two textboxes txtStartDate and txtEndDate and "Go Back" Button(html input button having similar functionality as that of Backbutton of browser)

When "Go Back" is Clicked  this goes to First.aspx .

I want that items should be added to the listbox of first.aspx

according to  conacated value of  txtStartDate and txtEndDate  of second.aspx

i have written code as follows but this is not working?

what may be going wrong?

 

Second Page
protected void Button1_ServerClick(object sender, EventArgs e)-------------------------------------->"Go Button"
    {
        ListBox s = (ListBox)PreviousPage.FindControl("ListDate");
        s.Items.Add(new ListItem(txtStartDate.Text + "-" + txtEndDate.Text));

    }

<input type="BUTTON" value="Go Back"
            onclick="history.go(-1)" id="Button1"   runat="server"  onserverclick=" Button1_ServerClick"/>

Swati

The answer was a bit long so I posted on our website.

please , see the link below

http://www.dotnet-friends.com/Tutorials/ASP/TUTinASP58575dd0-7349-4741-9deb-3c6998bf16dd.aspx

 

Happy Coding!

hi,

don't use history.go() to do that, coz history.go() just track the url of the page you just visited. After the previous page postbacks, it is destroyed.

so you want to access the ListBox in the previous page, it cannot find it.

try to store the textbox' value in session and then use Response.Redirect to the previous page

first page

public partial class _Default : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        if (Session["text1"] != null && Session["text2"] != null)
        {
            ListBox1.Items.Add(Session["text1"].ToString());
            ListBox1.Items.Add(Session["text2"].ToString());
         
        }
       
    }
    protected void Button1_Click(object sender, EventArgs e)
    {
        Response.Redirect("Default4.aspx");
    }
}

second page

public partial class Default4 : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
      
    }

  
    protected void Goback_Click(object sender, EventArgs e)
    {
        Session["text1"] = TextBox1.Text;
        Session["text2"] = TextBox2.Text;
        Response.Redirect("Default.aspx");
    }
}

First item is replaced with the second instead of getting added

 

first page

public partial class _Default : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        if (Session["text1"] != null && Session["text2"] != null)
        {
            ListBox1.Items.Add(Session["text1"].ToString());
            ListBox1.Items.Add(Session["text2"].ToString());
         
        }
       
    }
    protected void Button1_Click(object sender, EventArgs e)
    {
        Response.Redirect("Default4.aspx");
    }
}

second page

public partial class Default4 : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
      
    }

  
    protected void Goback_Click(object sender, EventArgs e)
    {
        Session["text1"] = TextBox1.Text;
        Session["text2"] = TextBox2.Text;
        Response.Redirect("Default.aspx");
    }
}

 

 i have already tried that,

But First item in the listbox is replaced with the second one ,

As Postback occurs ,thats why i have tried with history.go(-1),

Is there any other way to keep the items without replacing

Swati

Hi,
Session is a key-value pair collection, and the value added in the second page has the same key with the previous one, so the value will be replaced.
Keep the items in a array, and store the whole array in the session.
in page 1:
if (Session["list"] != null)
{
ArrayList al = Session["al"] as ArrayList;
for( int i = 0; i < al.Count; i++ )
ListBox1.Items.Add(al[i]);
}

in page 2:
ArrayList al;
if (Session["list"] != null)
{
al = Session["al"] as ArrayList;
}
else
{
al = new ArrayList();
Session["list"] = al;
}
al.Add("new item");
Hope it helps.